Question 1003673: The product of two consecutive positive integers is 119 more than the next integers. What is the largest of the three integers?
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9 Found 2 solutions by MathLover1, stanbon:Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
let the three consecutive positive integers be ,,and
if the product of two consecutive positive integers is more than the next integer, we have
........since given that integers are positive
solution we need is:
so,
first integer is:
second integer is:
third integer is:=>the largest of the three integers
You can put this solution on YOUR website! The product of two consecutive positive integers is 119 more than the next integers. What is the largest of the three integers?
1st:x-1
2nd:x
3rd:x+1
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Equation:
(x-1)x = x+1+119
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x^2 - x = x + 120
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x^2 - 2x - 120 = 0
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(x-12)(x+10) = 0
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x = 12
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Largest = x+1 = 13
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Cheers,
Stan H.
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