SOLUTION: The product of two consecutive integers is 119 more than the next integer. What is the largest of the three integers? 11 13 14 9 Thank you.

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Question 1003672: The product of two consecutive integers is 119 more than the next integer. What is the largest of the three integers?
11
13
14
9
Thank you.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let the three consecutive positive integers be x,x%2B1,and x%2B2
if the product of two consecutive positive integers is 119 more than the next integer, we have
x%28x%2B1%29=%28x%2B2%29%2B119
x%5E2%2Bx=x%2B121
x%5E2%2Bx-x=121
x%5E2=121
x=sqrt%28121%29........since given that integers are positive
solution we need is:x=11
so,
first integer is:11
second integer is:12
third integer is:13=>the largest of the three integers