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Question 1003646: Find three consecutive integers such that the product of the smallest and the largest is one less than 9 times the middle integer.
Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! Let n be the smallest integer. Then
n(n+2)=9(n+1)-1
n^2+2n=9n+8
n^2-7n-8=0
(n-8)(n+1)=0
n=8,-1
Assuming positive integers, then your consecutive integers are 8,9,and 10!!!!!!!!!!!!!!
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