Question 1003640: polygon k has 36 more diagonals and 3 more sides than polygon L. How many sides do each of these polygons have Found 2 solutions by ikleyn, KMST:Answer by ikleyn(52800) (Show Source):
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Polygon K has 36 more diagonals and 3 more sides than polygon L.
How many sides do each of these polygons have?
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An n-sided convex polygon has diagonals.
Let n be the number of sides of the polygon K.
Then it has diagonals.
The polygon L has n+3 sides and diagonals.
We are given that
- = 36.
Solve this equation for n.
(n+3)*n - n*(n-3) = 72,
6n = 72,
n = = 12.
Answer. K is 12-sided polygon and L is 15-sided polygon.
A polygon with sides has vertices.
Each vertex can be connected to each of the other vertices by a segment.
Two of those segments will be sides, connecting adjacent vertices.
The other segments will be diagonals.
Each of the vertices is involved in diagonals,
but since each diagonal involves vertices,
the total number of diagonals for polygon with sides is .
The total number of diagonals for polygon with sides is .
The total number of diagonals for polygon with sides is .
The problem says that .
We solve for .
Polygon K has sides, and polygon L has sides.