SOLUTION: We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=

Click here to see ALL problems on logarithm

Question 1003625: We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=y-1. I don't know what to do with the logs. If the logs were not there I would solve with the substitution method, I would solve for y in x=y-1,y=x+1. Plug that into the x^2 problem. A log is log 10^1. I'm stuck.
Found 2 solutions by KMST, MathTherapy:
Answer by KMST(5397) (Show Source):
You can put this solution on YOUR website!
To get rid of the logs, try the substitution ,
---> ---> .

Answer by MathTherapy(10858) (Show Source):
You can put this solution on YOUR website!

We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=y-1. I don't know what to do with the logs. If the logs were not there I would solve with the substitution method, I would solve for y in x=y-1,y=x+1. Plug that into the x^2 problem. A log is log 10^1. I'm stuck.

----------- Converting to EXPONENTIAL form -------- eq (i)

------------- Converting to EXPONENTIAL form --------- eq (ii)
------ Substituting for x in eq (i)

y + 3 = 2y � 2 ----------- Bases are equal and so are the exponents
y � 2y = - 2 � 3
- y = - 5
y = , or 5
--------- Substituting 5 for y in eq (ii)
, or x = 10,000
Solution set: