SOLUTION: We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=
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Question 1003625: We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=y-1. I don't know what to do with the logs. If the logs were not there I would solve with the substitution method, I would solve for y in x=y-1,y=x+1. Plug that into the x^2 problem. A log is log 10^1. I'm stuck. Found 2 solutions by KMST, MathTherapy:Answer by KMST(5328) (Show Source):
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We are doing systems of nonlinear equations in two variables. So solving with either the addition method or substitution method. The problem is solve the systems log x^2=y+3 log x=y-1. I don't know what to do with the logs. If the logs were not there I would solve with the substitution method, I would solve for y in x=y-1,y=x+1. Plug that into the x^2 problem. A log is log 10^1. I'm stuck.
----------- Converting to EXPONENTIAL form -------- eq (i)
------------- Converting to EXPONENTIAL form --------- eq (ii)
------ Substituting for x in eq (i)
y + 3 = 2y – 2 ----------- Bases are equal and so are the exponents
y – 2y = - 2 – 3
- y = - 5
y = , or 5
--------- Substituting 5 for y in eq (ii) , or x = 10,000
Solution set:
