SOLUTION: Suppose the perimeter of a rectangle is 33 cm and the area is 65 square cm. what are the dimensions of the original rectangle?

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Question 1003571: Suppose the perimeter of a rectangle is 33 cm and the area is 65 square cm. what are the dimensions of the original rectangle?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Study this lesson:
http://www.algebra.com/my/FIND-RECTANGLE-DIMENSIONS-USING-GIVEN-PERIMETER-AND-AREA.lesson?content_action=show_dev

More specifically you can solve this system:
system%282x%2B2y=33%2Cxy=65%29 using the dimensions as x and y.


You should obtain a quadratic equation, 2x%5E2-33x%2B130=0 and find the dimensions are 13%2F2 and 10.


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The quadratic equation is not factorable with integer constants. Use the formula for general solution to a quadratic equation. The two roots are the dimensions of the rectangle. The values will come directly from the use of the formula to solution of a quadratic equation.
x=%2833%2B-+7%29%2F4