SOLUTION: Suppose you go to the store to buy some tapes and CDs. The store only has 7 CDs and 10 tapes available for sale. You want at least 4 CDs and at least 10 hours of recorded music. Ea

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Suppose you go to the store to buy some tapes and CDs. The store only has 7 CDs and 10 tapes available for sale. You want at least 4 CDs and at least 10 hours of recorded music. Ea      Log On


   



Question 1003487: Suppose you go to the store to buy some tapes and CDs. The store only has 7 CDs and 10 tapes available for sale. You want at least 4 CDs and at least 10 hours of recorded music. Each tape holds about 45 minutes of music, and each CD holds about an hour. If tapes cost $8 each and CDs cost $12 each, what is the least amount of money you can spend to get what you want?
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Convert hours to minutes: 1 hour= 60 minutes; 10 hours= 600 minutes.
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4(60)+x(45) >= 600
240+x45>= 600
x45 >= 360
x >= 8 IF you get 4 CDs, you need 8 tapes to get at least 10 hours of music.
4 CDs * 12= 48
8 tapes* 8= 64
_ _ _ _ -------
Total........$112