SOLUTION: Solve on interval [0,360] 2cos^2x=1 3cot^2x=1 Csc^2x-cscx

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Question 1003485: Solve on interval [0,360]
2cos^2x=1
3cot^2x=1
Csc^2x-cscx
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
2cos%5E2%28x%29 = 1,

cos%5E2%28x%29 = 1%2F2,

cos%28c%29 = +/- sqrt%282%29%2F2,

cos%28x%29 = sqrt%282%29%2F2     ----->  x = 45°,  315°

cos%28x%29 = -sqrt%282%29%2F2     ----->  x = 135°,  225°.

Answer.  45°,  135°,  225°,  315°.