SOLUTION: Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
y=
x=
(x,y)=
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
y=
x=
(x,y)=
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Question 1003368: Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
y=
x=
(x,y)= Found 3 solutions by lwsshak3, ikleyn, josgarithmetic:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
= x^2 + 6x-1=0
x^2 +6x=1
x^2+6x+9=1+9
(x+3)^2=10
(x+3=±√10
x=-3±√10
You can put this solution on YOUR website! .
Use the method of completing the square to find the standard form of the quadratic function.
f(x) = x^2 + 6x − 1
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The problem's formulation in the post is absolutely illiterate from the Math point of view,
since the given function is JUST WRITTEN in the standard form.
(