SOLUTION: f(x) = 2x^2 + 3x + 1 find the minimum value of the function

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Question 1003346: f(x) = 2x^2 + 3x + 1
find the minimum value of the function
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 2x^2 + 3x + 1
find the minimum value of the function
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min occurs at x = -b/(2a) = -3/(4) = -3/4
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min value = f(-3/4) = 2(9/16) + 3(-3/4) + 1 = (18/16) -(36/16) + 16/16 = -1/8
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Cheers,
Stan H.
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