SOLUTION: Mike has $9.85 in dimes and quarters. If there are 58 coins altogether, how many dimes and quarters does mike have?

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Question 1003075: Mike has $9.85 in dimes and quarters. If there are 58 coins altogether, how many dimes and quarters does mike have?
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Dimes = x
Quarters = y
x + y = 58.......(1)
10x + 25y = 985.......(20
Multiply Equation (1) by 10
10x + 10y = 580......(1)
10x + 25y = 985.......(2)
Subtract Eq (1) from Eq (2)
.....15y = 405
.......y = 27
Substitute y = 27 in Eq (1)
x + y = 58
x + 27 = 58
x = 58 - 27
x = 31
there are 31 Dimes and 27 Quarters
Hope this helps :-)