SOLUTION: how do you solve for Y=-(x+1)^2+3 when y=9

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Question 1003035: how do you solve for Y=-(x+1)^2+3 when y=9
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

y=-%28x%2B1%29%5E2%2B3 when y=9
9=-%28x%2B1%29%5E2%2B3
9-3=-%28x%2B1%29%5E2
6=-%28x%2B1%29%5E2
%28x%2B1%29%5E2=-6
sqrt%28%28x%2B1%29%5E2%29=sqrt%28-6%29

x%2B1=sqrt%28-6%29
x=sqrt%28-6%29-1
x=%28-1%2B-i%2Asqrt%28-6%29%29
solutions:
x=%28-1%2Bi%2Asqrt%28-6%29%29
x=%28-1-i%2Asqrt%28-6%29%29