SOLUTION: Solve and check for extraneous solutions (3x-5)^(1/2)=x-1

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Question 1002959: Solve and check for extraneous solutions
(3x-5)^(1/2)=x-1
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(3x-5)^(1/2)=x-1
Square both sides
3x-5+=+x%5E2+-+2x+%2B+1
x%5E2+-+5x+%2B+6+=+0
(x-2)*(x-3) = 0
x = 2, 3
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You can do the check

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
3x-5=x%5E2-2x%2B1
x%5E2-2x-3x%2B1%2B5=0
x%5E2-5x%2B6=0

%28x-2%29%28x-3%29=0

Check if any of these will work:
x=2 or x=3

3*2-5=1, and sqrt(1) is good.

3*3-5=4, and sqrt(4) is good.

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Both solutions are good: x=2 or x=3.
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