SOLUTION: Not sure why this problem is such and issue for me. 1. What values for x must be excluded in the following fraction? -1/x-8

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Question 100293: Not sure why this problem is such and issue for me.
1. What values for x must be excluded in the following fraction?
-1/x-8

Found 2 solutions by tutorcecilia, bucky:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
Exclued (8) because if x=8, the denominator will equal zero which is undefined.
%28-1%2F%28x-8%29%29
Letting x=8 gives %28-1%2F%288-8%29%29
-1%2F0%29
undefined

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
You wrote that you were given -1/x-8 which, according to the rules of algebra means that
you do the divisions and multiplications first and the additions and subtractions next and
therefore you get:
.
-1%2Fx+-+8
.
but I suspect that you meant to write -1/(x-8) which means that you divide -1 by the quantity
x - 8 to get the fraction:
.
-1%2F%28x-8%29
.
In algebra, division by zero is not allowed. Therefore, the denominator x - 8 is not allowed
to equal zero. We can find the value of x that will make the denominator equal zero by
writing the equation:
.
x+-+8+=+0
.
Solve this equation by adding 8 to both sides to get:
.
x+=+8
.
When x equals 8 the denominator will be zero and we will have a division by zero. Therefore,
we cannot allow the value of x to be +8. Other than that, any other real value of x will be
OK ... anywhere from minus infinity to positive infinity ... except for +8.
.
Hope this helps you to understand the problem.
.