Question 1002908: The sum of three numbers is
106
. The first number is
8
less than the second. The third number is
4
times the second. What are the numbers? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The sum of three numbers is
106
. The first number is
8
less than the second. The third number is
4
times the second. What are the numbers?
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Equations:
a + b + c = 106
a = b-8
c = 4b
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Substitute for a and c; solve for "b"::
b-8 + b + 4b = 106
6b = 114
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b = 19
----
a = b-8 = 11
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c = 4b = 76
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Cheers,
Stan H.
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