SOLUTION: Lois rode her bike to visit a friend. She traveled at 10 mi/hr. While she was there, it began to rain. Her friend drove her home in a car traveling at 25 mi/hr. Lois took 1.5 h
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Lois rode her bike to visit a friend. She traveled at 10 mi/hr. While she was there, it began to rain. Her friend drove her home in a car traveling at 25 mi/hr. Lois took 1.5 h
Log On
Question 100290: Lois rode her bike to visit a friend. She traveled at 10 mi/hr. While she was there, it began to rain. Her friend drove her home in a car traveling at 25 mi/hr. Lois took 1.5 hr longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house? Need assistance in writing an equation as well as solving the problem. Thanks in advance from a confused parent! Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! distance(d)=rate(r) times time(t) or d=rt; r=d/t and t=d/r
Let t=time it took Lois to ride home in the car
Then (t+1.5)=time it took Lois to bike to her friends
(1) distance she travelled on a bike=rt=10*(t+1.5)
(2) distance she travelled back in the car=25*t
Now we know that (1)distance going=(2)distance coming back in the car. So:
10(t+1.5)=25t get rid of parens
10t+15=25t subtract 10t from both sides
10t-10t+15=25t-10t collect like terms
15=15t divide both sides by 15
t=1 hour time it took to ride home in the car
t+1.5=1+1.5=2.5 hrs-------------------------time it took biking to her friends
CK
2.5*10=1*25
25=25
