Question 1002870: A soccer team has 3 more boys and 3/4 as many girls as last year. The number of players on the team is the same as last year. how many girls were on the team last year? There were 8 boys n the team last year.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! let b = number of boys last year.
let g = number of girls last year.
p is the number of players on the team last year and this year (stayed the same).
last year b + g = p
last year b was equal to 8, so last year 8 + g = p
this year b + 3 + 3/4 * g = p
since b was 8 last year, b + 3 = 11 this year, so 11 + 3/4 * g = p
you have 2 equations that need to be solved simultaneously.
they are:
8 + g = p
11 + 3/4 * g = p
since p is equal to 8 + g in the first equation, you can replace p with 8 + g in the second equation to get:
11 + 3/4 * g = p becomes:
11 + 3/4 * g = 8 + g
subtract 3/4 * g from both sides of the equation and subtract 8 from both sides of the equation to get:
11 - 8 = g - 3/4 * g
combine like terms to get:
3 = 1/4 * g
multiply both sides of the equation by 4 to get:
12 = g
your solution is that b = 8 and g = 12
last year b + g = p becomes 8 + 12 = 20.
this year b + 3 + 3/4 * g becomes 8 + 3 + 3/4 * 12 which becomes 11 + 9 = 20.
your solution is confirmed to be correct.
your solution is:
the numbr of girls on the team last year was 12.
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