SOLUTION: Three apples and two oranges cost $1.25, while two apples and one orange cost 75 cents. At this rate, find the cost of six apples and one orange to the nearest cents?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Three apples and two oranges cost $1.25, while two apples and one orange cost 75 cents. At this rate, find the cost of six apples and one orange to the nearest cents?      Log On


   

Question 1002844: Three apples and two oranges cost $1.25, while two apples and one orange cost 75 cents. At this rate, find the cost of six apples and one orange to the nearest cents?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
x, apple price
y, orange price

system%283x%2B2y=1.25%2C2x%2By=0.75%29

Using Elimination Method
system%283x%2B2y=1.25%2C4x%2B2y=1.50%29

4x%2B2y-3x-2y=1.50-1.25
highlight%28x=0.25%29------how many dollars for one apple

2x%2By=0.75
y=0.75-2x
y=0.75-2%280.25%29
highlight%28y=0.25%29-----one orange ALSO costs 0.25 dollars.