SOLUTION: The larger of three numbers is twice the middle number. The smaller of the three number is five less than the middle number. If the sum of the three numbers is 43, find the numbers
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: The larger of three numbers is twice the middle number. The smaller of the three number is five less than the middle number. If the sum of the three numbers is 43, find the numbers
Log On
Question 1002759: The larger of three numbers is twice the middle number. The smaller of the three number is five less than the middle number. If the sum of the three numbers is 43, find the numbers Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! So the large number and the smaller number are both relative to the middle number. Let's find the middle number, let's call it x. The large number will be l and the small number s:
2x= l
x-5= s
-----------------
s+x+l= 43 Substitute in this equation with above values
x-5+x+2x= 43 Add 5 on both sides:
x+x+2x= 48
4x= 48
x= 12 This is the middle number. The small number is:
x-5= s
12-5= 7 is the small number. And the large number:
2x=l
2(12)= l
l= 24 This is your big number
-----------------
Proof:
7+12+24= 43 We have the correct answer
