SOLUTION: Did I solve these right? 1. f(x)= -3x + 1 g(x)= -4x^2 + x + 2 Find g(f(x) ) -4(-3x+1)^2+(-3x+1)+2 -4(-3x+1)^2-3x+1+2 3-3x-4(-3x+1)^2 3-3x-4+24x-36x^2 =21x-36^2-1 2.f(x

Algebra ->  Rational-functions -> SOLUTION: Did I solve these right? 1. f(x)= -3x + 1 g(x)= -4x^2 + x + 2 Find g(f(x) ) -4(-3x+1)^2+(-3x+1)+2 -4(-3x+1)^2-3x+1+2 3-3x-4(-3x+1)^2 3-3x-4+24x-36x^2 =21x-36^2-1 2.f(x      Log On


   



Question 1002752: Did I solve these right?
1. f(x)= -3x + 1
g(x)= -4x^2 + x + 2
Find g(f(x) )
-4(-3x+1)^2+(-3x+1)+2
-4(-3x+1)^2-3x+1+2
3-3x-4(-3x+1)^2
3-3x-4+24x-36x^2
=21x-36^2-1

2.f(x)= -2x + 1
g(x)= -3x^2 -x -1
Find (g /f)(x)
-3x^2-x-1/-2x+1

3. f(x)=-x +2
g(x)= -4x2 + x + 5
Find (f o g)(x)
f(-4x^2+x+5)
-(-4x^2+x+5)+2
=4x^2-x-5+5
=4x^2-x

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


For 1, you left the variable out of the high order term. Chalking that up to a simple typo, you have it technically correct. However, I would have expressed my answer as:



keeping with the convention of writing the terms in descending order.

2 is spot on IF you were not required to express the rational function result in the form of

3. How you got from



to



I cannot fathom.

Should have been





John

My calculator said it, I believe it, that settles it