SOLUTION: The length of a rectangle is 5 ft longer than twice the width, if the perimeter is 58 ft, find the length and width of the rectangle
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Question 1002744: The length of a rectangle is 5 ft longer than twice the width, if the perimeter is 58 ft, find the length and width of the rectangle Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Call length and width, L and W.
P = 2L + 2W = 58
and
L = 5 + 2W
Substitute this into the first equation and get
2(5+2W) + 2W = 58
10 + 4W + 2W = 58
6W + 10 = 58
6W = 48
W = 8 ft
L = 21 ft
