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Re-write the polynomial:
y=-x^2+4 [the slope is negative, so the parabola will open downwards]
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To find the line of symetry, use the formula for finding the x-value of the vertex: -b/2a
Let y=-x^2+0x+4
Let a=-1
Let b=0
Let c=4
So, -b/2a=-(0)/(2)(-1)=0/-2=0
Therefore, the line of symetry is located at x=0 or the y-axis.
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To find the x-intercepts, plug the values into the quadratic formula and solve:
Let y=-x^2+0x+4
The result is x=-2 or x=2
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Graphing: