SOLUTION: Hi,
I would just like to say thank you for your help in advanced.
My question is as follows:
The arm of an indrustrial robot starts at a speed Vo and drops 34.8 cm in 4.2
Question 1002246: Hi,
I would just like to say thank you for your help in advanced.
My question is as follows:
The arm of an indrustrial robot starts at a speed Vo and drops 34.8 cm in 4.28 seconds, at constant acceleration a. Its motion is described by
s= Vot + (at^2)/2
or
34.8 = 4.28Vo + [a(4.28)^2]/2
In another trial the arm is found to drop 58.3 cm in 5.57 seconds, with the same initial speed and acceleration. Find Vo and a.
Thank you
You can put this solution on YOUR website! The arm of an indrustrial robot starts at a speed Vo and drops 34.8 cm in 4.28 seconds, at constant acceleration a. Its motion is described by
s= (Vo)t + (at^2)/2
or
34.8 = 4.28Vo + [a(4.28)^2]/2
In another trial the arm is found to drop 58.3 cm in 5.57 seconds, with the same initial speed and acceleration. Find Vo and a.
you get s = 34.8 and t = 4.28
formula becomes:
34.8 = 4.28(Vo) + (a*4.28^2)/2
you have another trial where s = 58.3 and t = 5.57
formula becomes:
58.3 = 5.57(Vo) + (a*5.57^2)/2
since Vo and a remain the same in both equations, you have 2 equations that need to be solved simultaneously.