SOLUTION: Find the equation in the form of a(x-h)^2+k: Turning point: (1,1) y intercept: 0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the equation in the form of a(x-h)^2+k: Turning point: (1,1) y intercept: 0       Log On


   

Question 1002233: Find the equation in the form of a(x-h)^2+k:
Turning point: (1,1)
y intercept: 0

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Find the equation in the form of a%28x-h%29%5E2%2Bk: it is a parabola
Turning point: (1,1) -> turning point of a parabola is vertex
so, (1,1)=(h,k)
y-intercept: 0+=>(0,0)
y=a%28x-h%29%5E2%2Bk....if (1,1)=(h,k)
y=a%28x-1%29%5E2%2B1......eq.1
y=a%28x-1%29%5E2%2B1....if (0,0)
0=a%280-1%29%5E2%2B1
-1=a%281%29
-1=a

y=-1%28x-1%29%5E2%2B1 or
y=-%28x-1%29%5E2%2B1

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-%28x-1%29%5E2%2B1%29+