SOLUTION: a rectangular shaped parking lot is to have a perimeter of 524 yards. if the width must be 58 yards becuase of a building code, what will the length need to be?

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Question 100220: a rectangular shaped parking lot is to have a perimeter of 524 yards. if the width must be 58 yards becuase of a building code, what will the length need to be?
Found 2 solutions by edjones, smik:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
P=2(L+W)
W=58
524=2(L+58)
524=2L+116
524-116=2L
408=2L
L=408/2
L=204 yards
Ed

Answer by smik(40) About Me  (Show Source):
You can put this solution on YOUR website!
Good question. Let's work through this step by step.


We have two pieces of information:
1. The perimeter has to be - 524 yards.
2. The width has to be - 58 yards.


Now, since it's a rectangle two sides are going to be 58 yards. That accounts for 116 yards (2*58). So, we can subtract and see what has to be accounted for:


524 - 116 = 408 yards


We also know that the remaining two sides have to be equal in length. So if one side was 'x' then 2*x would have to be 408 yards. (We have an equation).


2x = 408 (divide both sides by 2)
x = 204


Hence, the length is 204 yards.