SOLUTION: -4 sq root3 - sq root36 + 3 sq root 48 =?
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Question 100210
:
-4 sq root3 - sq root36 + 3 sq root 48 =?
Answer by
stanbon(75887)
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-4 sq root3 - sq root36 + 3 sq root 48 =?
= -4sqrt(3) - 6 + 3sqrt(16)*sqrt3
= -4sqrt(3) -6 +3*4sqrt(3)
= -4sqrt(3) - 6 + 12sqrt(3)
= 8sqrt(3) - 6
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Cheers,
Stan H.