The question is:
how long would each take to do the job alone?
Let x = the number of days it takes for A to do 1 job.
Then A's rate in jobs per day is 1 job per x days or 1/x jobs per day.
Let y = the number of days it takes for B to do 1 job.
Then B's rate in jobs per day is 1 job per y days or 1/y jobs per day.
A and B together can finish a job in 36 days.
Then their combined rate is 1 job per 36 days, or 1/36 jobs per day.
The sum of their rates equals 1/36 jobs per day.
1/x + 1/y = 1/36
If A can do as much work in 4 days as B can do in 9 days,
We use rate×time to determine what part of a job is done by A
in 4 days and what part of a job is done by B in 9 days, and
set those equal to each other:
4/x = 9/y
or
4/x - 9/y = 0
The system of equations is
Do not clear of fractions. Instead eliminate 1/y
by multiplying the first equation through by 9
Adding the two equations:
cross multiply
x = 52 days = how many days it takes for A to do the job.
Substitute in
Cross multiply
y = 117 days = how many days it takes for B to do the job.
Edwin