Question 1001637: Please help me and show steps. I have did this question 10 times and still comes up with the wrong answers. Thanks
A movie theater has a seating capacity of 333. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 2422, How many children, students, and adults attended?
These are the answers I got.
children 144
students 120
adults 69
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website! The seating capacity but no given total number of attendees suggests this includes an inequality.
c children, s students, a adults;
 ----Half as many adults as children;
Account for ticket sales: 
and then sub for a: 
Account for seating capacity: 
and subst for a: 
You have two algebraic statements in the unknown variables c and s. You COULD be looking for a solution for c, s, a, which is an inequality, or a set of combinations of these variables. You might simply try to use both statements as equations assuming capacity was full.
Maybe work with ticket sales equation this way:
-
Now you MIGHT want to try to graph this system of statements and look for the whole number solution values for s and c:
My guess, without having tried fully yet, is that your desired points (c,s) might be ON the line; maybe, just maybe, the intersection might work, but ...?
You would want a solution which is ON THE line in order to be consistent with ticket sales.
Answer by MathTherapy(10555)  (Show Source):
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