SOLUTION: A farmer builds a rectangular grid of pens with 1 row and 4 columns using 850 feet of fencing. What dimensions will maximize the total area of the pen? Really confused on how t

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Question 1001620: A farmer builds a rectangular grid of pens with 1 row and 4 columns using 850 feet of fencing. What dimensions will maximize the total area of the pen?
Really confused on how to do this problem. Any help would be great!

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
system%28W=width%2CL=length%29 of that rectangular row of pens.
system%285W%2B2L=850%2CArea=W%2AL%29--->system%282L=850-5W%2CArea=W%2AL%29--->system%28L=%28850-5W%29%2F2%2CArea=W%2AL%29--->system%28L=425-2.5W%2CArea=W%2AL%29--->system%28L=425-2.5W%2CArea=W%2A%28425-2.5W%29%29
The equation Area=W%2A%28425-2.5W%29 shows that Area is a quadratic function of W .
If we graphed it, it would be a parabola with a vertical axis
(parallel to the Area axis),
going through a maximum.


You may prefer to use variables/formats/formulas/recipes that are customary in algebra.
In that case you would call the width x and the total area of the pens y ,
and you would write y=x%28425-2.5x%29<-->y=-2.5x%5E2%2B425x .
Then you would use the formula to find the maximum of a quadratic function:
x=-b%2F2a for the function y=ax%5E2%2Bbx%2Bc .
In this case a=-2.5 and b=425 so
x=-425%2F%282%2A%28-2.5%29%29=425%2F5=85 .

WITHOUT FORMULAS:
If we graphed Area=W%2A%28425-2.5W%29 as a function of W ,
it would be a parabola with a vertical axis
(parallel to the Area axis),
going through a maximum.
We are trying to find the width W at that maximum.
Area=0 for W=0 and 425-2.5W=0<-->425=2.5W<-->425%2F5=W<-->W=170 .
Since parabolas are symmetrical, the axis (and vertex/maximum)
is halfway between W=0 and W=170 at W=%280%2B170%29%2F2=highlight%2885%29 .
For W=85 , L=425-2.5W=425-212.5=highlight%28212.5%29 .
So, the dimensions that maximize total area are
highlight%2885ft%29 for the width of the row of pens,
highlight%28212.5ft%29 for the length of the row of pens,
and if you wanted the 4 pens to be of equal size, each pen would measure 85ft by
212.5ft%2F4=%2853.125ft%29 .