SOLUTION: A collection of coins has a value of 64 cents. There are two more nickels than dimes and three times as many pennies as dimes. How many of each kind of coin are there?
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Question 1001562: A collection of coins has a value of 64 cents. There are two more nickels than dimes and three times as many pennies as dimes. How many of each kind of coin are there? Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! d = number of dimes
n = number of nickels
p = number of pennies
The problem says there are two more nickels than dimes and three times as many pennies as dimes:
d+2(0.05)= n
3d= p
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0.10d+0.05*n+0.001p= 0.64
Substitute by plugging into this equation the equivalent values above:
0.10*d + 0.05*d+2(0.05) + 0.01*3d= 0.64
Now solve for d:
0.10*d + 0.05*d+2(0.05) + 0.01*3d= 0.64
0.18d+0.10=0.64
0.18d= 0.54
d= 3 There are 3 dimes, and the problem says
n= d+2= 5 nickels and
p= 3d= 3*3= 9 pennies
3(0.10)+ 5(0.05)+9(0.01)= 0.64
0.30+0.25= 0.09= 0.64
0.64= 0.64 We have the correct answer
