SOLUTION: If the vertices of a parallelogram are (3,1), (8, 1), (6, 5), and (k, 5), a value of k may be? a) 10 b) 2 c) 0 d) 1

Algebra ->  Parallelograms -> SOLUTION: If the vertices of a parallelogram are (3,1), (8, 1), (6, 5), and (k, 5), a value of k may be? a) 10 b) 2 c) 0 d) 1      Log On


   

Question 1001379: If the vertices of a parallelogram are (3,1), (8, 1), (6, 5), and (k, 5), a value of k may be?
a) 10 b) 2 c) 0 d) 1
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Points (3,1) and (8,1) are on the horizontal line with y=1, 8-3=5 units apart.
Points (6,5) and (k,5) are on the horizontal line with y=5, parallel to y=1.
In a parallelogram, sides that are parallel are congruent,
so the distance between (6,5) and (k,5) must also be 5.
Either k=6+5=11, or k=6-5=highlight%281%29 .
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