SOLUTION: Do I have these formulas correct? Radioactive decay formula: {{{ A(t) = A(0) e^(-kt)}}} Radioactive half-life formula: {{{ A(t) = A(0)(1/2)^(t/h) }}} Exponential decay formula

Algebra ->  Equations -> SOLUTION: Do I have these formulas correct? Radioactive decay formula: {{{ A(t) = A(0) e^(-kt)}}} Radioactive half-life formula: {{{ A(t) = A(0)(1/2)^(t/h) }}} Exponential decay formula      Log On


   

Question 1001329: Do I have these formulas correct?
Radioactive decay formula: +A%28t%29+=+A%280%29+e%5E%28-kt%29
Radioactive half-life formula: +A%28t%29+=+A%280%29%281%2F2%29%5E%28t%2Fh%29+
Exponential decay formula: +A%28t%29+=+A%280%29e%5E%28-kt%29+
Exponential growth formula: +A%28t%29+=+A%280%29e%5E%28kt%29+
Also, Is the formula for radioactive decay the same as the formula for exponential growth?
Thank you
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Decay, A=A%5B0%5De%5E%28-kt%29, showing the 0 as a subscript;
The negative sign in the exponent is to help show that your equation is meant for decay, and this assumes k%3E0.
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Use the equation, or the format for either exponential decay or for radioactive decay, or any exponential continuous decay.


Exponential Growth, A=A%5B0%5De%5E%28kt%29.

You may choose to say A%28t%29 as the function name, for A being a function of t.

The half-life (for exponential decay) can be easily found picking A%5B0%5D=1 and A=1%2F2 and then solving for t. Usually you have some data for t and A and A%5B0%5D when you look for a value, because you may also want to find k.