SOLUTION: Solve the following equation: {{{ e^(2x)+4e^(x)-5 = 0 }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve the following equation: {{{ e^(2x)+4e^(x)-5 = 0 }}}      Log On


   

Question 1001258: Solve the following equation:
+e%5E%282x%29%2B4e%5E%28x%29-5+=+0+
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
e%5E%282x%29+%2B+4e%5E%28x%29+-+5 = 0

Factorize

%28e%5Ex+%2B+5%29%2A%28e%5Ex+-+1%29 = 0.

The only solution is

e%5Ex = 1,   i.e.   x = 0.