SOLUTION: Solve the following equations: {{{ 4^x=32 }}} {{{ 4^x=5 }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve the following equations: {{{ 4^x=32 }}} {{{ 4^x=5 }}}      Log On


   

Question 1001257: Solve the following equations:
+4%5Ex=32+
+4%5Ex=5+
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From +4%5Ex=32+
take the log of both sides and get
log 4^x = log 32
Apply the log rules and get
x*log 4 = log 32
x = log 32/log 4
Using the same method for the second one,
x = log 5/log 4