SOLUTION: log(x+3)-log(x-2)=4log2
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Question 1001217
:
log(x+3)-log(x-2)=4log2
Answer by
stanbon(75887)
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log(x+3)-log(x-2)=4log2
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log[(x+3)/(x-2)] = log(2^4)
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(x+3)/(x-2) = 16
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x+3 = 16x - 32
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15x = 35
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x = 7/3
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Cheers,
Stan H.
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