SOLUTION: Maria starts out jogging from Ye Olde Bridge at 8:00am at a speed of 4 mil/h. Twelve minutes later, Nicole starts out from Ye Olde Bridge and follows the same route. At what consta
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-> SOLUTION: Maria starts out jogging from Ye Olde Bridge at 8:00am at a speed of 4 mil/h. Twelve minutes later, Nicole starts out from Ye Olde Bridge and follows the same route. At what consta
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Question 1000930: Maria starts out jogging from Ye Olde Bridge at 8:00am at a speed of 4 mil/h. Twelve minutes later, Nicole starts out from Ye Olde Bridge and follows the same route. At what constant rate in miles per hour must Nicole run to catch Maria at 8:42am? Express your answer as a decimal to the nearest tenth. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Let us call Nicole's rate, r.
Since the distances are equal, and d=rt, we have
Maria's time = 42/60 hours = .7 hour and
Nicole's time = 30/60 = .5 hour so that
4(.7)=r(.5)
2.8 = .5r
r = 5.6 miles per hour
