SOLUTION: Where are the foci for the ellipse x^2/9+y^2/64=1?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Where are the foci for the ellipse x^2/9+y^2/64=1?      Log On


   



Question 1000756: Where are the foci for the ellipse x^2/9+y^2/64=1?
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Since this one is tall, not wide, the distance to the focus (from the origin) will be found by
c%5E2=b%5E2-a%5E2
c%5E2=64-9
c%5E2=55
c=sqrt%2855%29
and the points are
(0, sqrt(55)) and (0, -sqrt(55))