Question 1000724: In a collection of dimes, nickels, and quarters, there are twice as many dimes as nickels and 3 fewer quarters than dimes. If the total value of the coins $4.50, how many of each type of coin are there?
Found 2 solutions by addingup, stanbon:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! 7 nickels:.................0.35
Twice as many dimes: 14....1.40
3 fewer quarters: 11.......2.75
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*****************Total: ..4.50
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! In a collection of dimes, nickels, and quarters, there are twice as many dimes as nickels and 3 fewer quarters than dimes. If the total value of the coins $4.50, how many of each type of coin are there?
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Equations:
d = 2n
q = d-3
5n + 10d + 25q = 450
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Substitute for "n" and for "q" and solve for "d"::
5(d/2) + 10d + 25(d-3) = 450
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(5/2)d + 10d + 25d = 525
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37.5d = 525
d = 14 (# of dimes)
n = (d/2) = 7 (# of nickels)
q = d-3 = 11 (# of quarters)
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Cheers,
Stan H.
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