Question 1000537: Write the point-slope form of the equation of the line described.
through: (-5,1), parallel to y=-6x/5
Write the slope-intercept form of the equation of the line described.
through: (2,-4), perpendicular to y= 3x/7+2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write the point-slope form of the equation of the line described.
through: (-5,1), parallel to y=-6x/5
slope = -6/5
Form:: y = mx + b
Solve for "b"::
1 = (-6/5)(-5) + b
b = -5
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Equation:: y = (-6/5)x - 5
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Write the slope-intercept form of the equation of the line described.
through: (2,-4), perpendicular to y= 3x/7+2
slope = -7/3
Form: y = mx + b
Solve for "b"::
-4 = (-7/3)2 + b
-12/3 = -14/3 + b
b = 2/3
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Equation:
y = (-7/3)x + 2/3
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Cheers,
stan H.
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