SOLUTION: how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution?

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Question 100051: how many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
x(40%)+(20-x)(65%)=20(50%)

.4x+13-.65x=10 ... 3=.25x ... 12=x