SOLUTION: http://www.usatestprep.com/modules/gallery/files/5/563/563.png Which of the sets of points lies on the line graphed here? A) {(0, 0), (1, 1), and (2, 2)} B) {(1, 1), (1, 2)

Algebra ->  Linear-equations -> SOLUTION: http://www.usatestprep.com/modules/gallery/files/5/563/563.png Which of the sets of points lies on the line graphed here? A) {(0, 0), (1, 1), and (2, 2)} B) {(1, 1), (1, 2)      Log On


   



Question 1000419: http://www.usatestprep.com/modules/gallery/files/5/563/563.png
Which of the sets of points lies on the line graphed here?
A)
{(0, 0), (1, 1), and (2, 2)}
B)
{(1, 1), (1, 2), and (2, 3)}
C)
{(0, 0), (-1, 1), and (1, 2)}
D)
{(0, 0), (-1, 1), and (1, -1)}

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

answer is:
D)
{(0,+0), (-1, 1), and (1, -1)}
check:
the equation of the line passing through points (0,+0), (-1) is:
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, 0) and (x2, y2) = (-1, 1).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%281-0%29%2F%28-1-0%29+=+-1.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1%2A0+%2Bb+=+0. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0--1%2A0+=+0.

y=(-1)x + (0)

Your graph:



so, the equation of your line is y=-x
check now all three points and see that all of them lie on the same line: