SOLUTION: Log base 3 of (2-3x) = log base 9 of (6x^2 - 19x + 2)
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Question 1000274
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Log base 3 of (2-3x) = log base 9 of (6x^2 - 19x + 2)
Answer by
MathLover1(20850)
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........change the base to base
.....cross multiply
...if log same, than we have
if
=>
if
=>
