SOLUTION: I usually know how to do questions involving substitution but this one is really proving difficult
x/3+y/2=-4
x-3y=6
I tried substituting for the x but I'm not even sure
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-> SOLUTION: I usually know how to do questions involving substitution but this one is really proving difficult
x/3+y/2=-4
x-3y=6
I tried substituting for the x but I'm not even sure
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Question 1000186: I usually know how to do questions involving substitution but this one is really proving difficult
x/3+y/2=-4
x-3y=6
I tried substituting for the x but I'm not even sure where to go from there Found 3 solutions by josgarithmetic, addingup, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! x/3+y/2=-4
x-3y=6
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Let's begin by getting the fractions out of the way. On the first equation, multiply both sides by 6 (because 6 is a common denominator for 3 and 2):
x/3+y/2=-4
6(x/3)+6(y/2)= 6(-4)
2x+3y= -24 This is now our 1st equation.
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x-3y= 6 Add 3y on both sides:
x= 6+3y Now let's substitute this value for x:
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2(6+3y)+3y= -24
12+6y+3y= -24 Subtract 12 from both sides and add y on left
9y= -36 Divide by 9
y= -4
And we said that x was:
x= 6+3y
x= 6+3(-4)
x= 6+-12
x= - 6
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Proof:
x/3+y/2=-4
-6/3+-4/2= -4
-2+-2= -4 We have the correct answer here. You do the same with the other equation and you'll find we have the correct answer.
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Now let’s find x:
x= 6+3(-4)
x= 6- 12
x= -6
You can put this solution on YOUR website!
I usually know how to do questions involving substitution but this one is really proving difficult
x/3+y/2=-4
x-3y=6
I tried substituting for the x but I'm not even sure where to go from there
2x + 3y = - 24 -------- Multiplying by LCD, 6 ------- eq (i)
x - 3y = 6 -------- eq (ii)
3x = - 18 , or
Now all you have to do is substitute - 6 for x in any of the 2 original equations to determine the value of y
You can solve eq (ii) for x to get: x = 6 + 3y, but after multiplying the 1st equation by 6, it's obvious
that y can immediately be eliminated to get the value of x