SOLUTION: A rectangular fish pond is 8ft longer than it is wide. A wooden walk 2 ft wide is placed around the pond. The area covered by the pond and walk is 160 ft squared greater than the a
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Question 1000135: A rectangular fish pond is 8ft longer than it is wide. A wooden walk 2 ft wide is placed around the pond. The area covered by the pond and walk is 160 ft squared greater than the area covered by the pond alone. What are the dimensions of the pond? Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! Area of the pond plus the wood walk:
A+160 = (W+12) * (W+4) = W^2 + 16W + 48
Area of the pond alone:
A= (W+8)*W= W^2+8W
Now we have a system with two equations and two unknowns.
Let’s solve by subtracting the first equation from the second:
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Now subtract 48 on both sides:
8W= 112 Divide both sides by 8:
W= 14 is the width of the pond. The length is:
14+8= 22. The area of the pond is:
14*22= 308 The area of the pond with the walkway:
(14+4)*(22+4)= 18*26= 468
Now, the problem says the area with the walkway is 160 more. Let's see if we have the correct answer:
468-308= 160 We have the right answer.
