Question 1000084: Given that the sides of an equilateral triangle is 4a + 6,3b - 2a, and 2b + 2 respectively find the perimeter of the triangle
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! All three sides are equal (4a + 6,3b - 2a, and 2b + 2)...
so set the first two equal and get
4a + 6 = 3b - 2a
or
6a - 3b = -6
or
2a - b = -2
Then set the last two equal and get
3b-2a=2b+2
or
b - 2a = 2
or
2a - b = -2 (same information)
Then the first and third and get
4a + 6 = 2b + 2
or
4a - 2b = -4
or
2a - b = -2 (same information)
Thus you cannot find both a and b, but you can
express all three sides in terms of a, since
b = 2a + 2
Thus the three sides added are (4a + 6)+(3b - 2a)+(2b + 2) =
4a + 6 + 3(2a + 2) - 2a + 2(2a +2) + 2 =
12a + 18
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