SOLUTION: A piece of Capillary tubing was Calibrated in the Following Manner. A clean Sample of Mass 3.247 g . A thread of Mercury, drawn into the tube a length of 23.75 mm as observed unde
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Question 1193642: A piece of Capillary tubing was Calibrated in the Following Manner. A clean Sample of Mass 3.247 g . A thread of Mercury, drawn into the tube a length of 23.75 mm as observed under microscope . The mass of Tube and Mercury was 3.489 g. The Density of Mercury is 13.60 g/cm^3 .Assuming that the capillary bore is a uniform cylinder, find the diameter of the bore if the volume of a cylindrical object is V= pie r^2 h Answer by ikleyn(52778) (Show Source):
The mass of the Mercury is the product of the bore volume by the density "d" of Mercury
3.247 = ,
or
3.247 = ,
where 2.375 is the length of 23.75 mm, converted to centimeters.
From the formula,
= = 0.032015,
r = = 0.1789 cm = 1.789 mm.
ANSWER. The diameter of the bore is 2r = 2*1.789 mm = 3.578 mm.
