Tutors Answer Your Questions about Travel Word Problems (FREE)
Question 195454: The period T (time in seconds for one complete cycle) of a simple pendulum is related to the length L (in feet) of the pendulum by the formula 8T2 = 2L. If a child is on a swing with at 10-foot chain, then how long does it take to complete one cycle of the swing?
8T2 = 2L =
8T2 = 3.142(10)=
8T2 = 9.86(10)= 98.60
8T2 = 398.60
Click here to see answer by vleith(2983)  |
Question 195410: Respected sir,
1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ?
2] Ritu goes to school at 10 kmph & reaches the school 6 minutes late.Nwxt day, she covers this distance at 12 kmper hour & reaches the school 9 minutes eariler than the scheduled time.what is the distance of her school from her house ?
plz sir help me to solve this arith problem.
waiting for yurs reply.
take care
thank u.
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 195494: a celebrity leaves a night club by car traveling at 1.5 miles per minute(90MPH)trying to avoid a tabloid photagrapher. One minute later, the photagrapher leaves the night club on his motorcycle, traveling at 2 miles per minute(120 MPH) in pursuit of the celeb. how long will it take the photographer to catch up with the celeb?
Click here to see answer by checkley77(12844) |
Question 195507: Respected sir,
1] A train travelling 25km an hour leaves Delhi at 9 a.m. & another train travelling 35 km an hour starts at 2 p.m. in the same direction . how many km from Delhi are they together ?
2] Walking 3/4 of his usual rate,a man is 1 1/2 (one an half hour) hours too late.find his usual time.
plz sir solve my difficulty as soon as possible.
thank u.
Click here to see answer by ejazali_syed(7) |
Question 195539: Adriana's 18-kilometer boat trip downriver took two hours, but the return trip back upstream took three hours. Figure the speed of the boat in still water and the speed of the current of the river.
Click here to see answer by anantha(86) |
Question 195718: A baseball player has hit a ball. The height, y, of the ball x seconds after it is hit is given by y= -16x^2 + 80x + 3.
At what time will the ball reach its maximum height? I used the quadratic formula and my answer was 2.04
What is the maximum height of the ball? I used the original formula.My answer was 232.78
When will the ball hit the ground? My answer was 4.08
Is this right??
thanks
Click here to see answer by jim_thompson5910(35256) |
Question 195718: A baseball player has hit a ball. The height, y, of the ball x seconds after it is hit is given by y= -16x^2 + 80x + 3.
At what time will the ball reach its maximum height? I used the quadratic formula and my answer was 2.04
What is the maximum height of the ball? I used the original formula.My answer was 232.78
When will the ball hit the ground? My answer was 4.08
Is this right??
thanks
Click here to see answer by Alan3354(69443)  |
Question 195768: respected sir,
1] A hare sees a dog 100 metres away from her,& scuds off in the opposite direction at a speed of 12 km an hour.A minute later the dog perceives her & gives chase at a speed of 16 km per hour.How soon will the dog overtake the hare ,& at what distance from the spot whence the hare took flight ?
2] A carriage driving in a fog passed a man who was walking at the rate of 3 km an hour in the same direction.He could see the carriage for 4 min.& it was visible to him upto a distance of 100 m. what was the speed of the carriage ?
plz explain me this sums...waiting for yurs reply.
thank u.
Click here to see answer by josmiceli(19441)  |
Question 196294: Two trains leave the station at the same time going in the same direction on parallel tracks. The freight train is going 42 mph and the other, a passenger train, is going 54mph. After how long will the trains be 324 miles apart?
Click here to see answer by checkley77(12844) |
Question 196209: Cabrina and Dabney are attending a conference. After the conference, Cabrina drives home to Boise at an average speed of 75 mph and Dabney drives home to Portland at an average speed of 60 mph. If the sum of their driving time is 11.3 hours and the sum of distance driven is 783 miles, determine the time each woman spent driving home.
Click here to see answer by ankor@dixie-net.com(22740) |
Question 196584: A passenger train leaves a train station four hours after a freight train leaves the same station. The freight train is traveling ten mph slower than the passenger train. Find the rate of the passenger train if the passenger train overtakes the freight train in 20hours.
Click here to see answer by Alan3354(69443) |
Question 196697: I have been having major trouble figuring the formula for area. Thank you for your help. Area of a painting. A rectangular painting with a width of
x centimeters has an area of x2 50x square centimeters.
Find a binomial that represents the length.
Click here to see answer by Alan3354(69443) |
Question 196839: Word problems are my toughest challenge. For example;
Draining the vat. With only the small valve open, all of
the liquid can be drained from a large vat in 4 hours. With
only the large valve open, all of the liquid can be drained
from the same vat in 2 hours. How long would it take to
drain the vat with both valves open? How do I figure out the time it takes to drain the vat? Thank you.
Click here to see answer by stanbon(75887) |
Question 197236: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 2.20 A.M. If train B oases the same station at 2:35 A.M., at what time will train B catch up to train A?
I honestly don't know where to begin solving this.
Click here to see answer by stanbon(75887) |
Question 197329: After leaving Moose Jaw, Hanson drove
200 kilometers at x km/hr and then decreased his speed by
20 km/hr and drove 240 additional kilometers. Write a rational expression for
his total traveling time. Evaluate the expression for x = 100.
Click here to see answer by stanbon(75887) |
Question 196885: We know how to find the time a falling object reaches the ground. We can use a similar technique to find the distance an object will travel, if it is launched, like a cannonball by a cannon (we assume no air friction). Let our cannon sit at x=0. Suppose it shoots a ball with an initial vertical velocity of v1, and horizontal velocity of v2. Physics will tell us that its trajectory will be given by the following argument: Vertical motion: y(t) = v1t -1/2gt^2 (we again assume y=0 is the ground). Horizontal motion: x(t) = v2t. Now we can eliminate t rrom these two equations, obtaining a relation between y and x (just solve for t in the second, and substitute t in the first with your expression from the second). The resulting function, y(x), tells us at what height the cannonball is, when it has traveled a distance x. Hence, the ball is on the ground when y(x) = 0. The equation will have two solutions in x: One will correspond to the starting position, when the ball was initially, and the other to the position at which it will land again. Solve the equation for the following values: g = 9.8 m/s^2. v1 = 10 m/s. v2 = 5 m/s.
Click here to see answer by solver91311(24713)  |
Question 197693: Sailboat speed. The sail area-displacement ratio S provides
a measure of the sail power available to drive a
boat. For a boat with a displacement of d pounds and a
sail area of A square feet S is determined by the formula
S = 16Ad 2/3.
a) Find S to the nearest tenth for the Tartan 4100, which
has a sail area of 810 square feet and a displacement of
23,245 pounds.
b) Write d in terms of A and S.
Click here to see answer by ankor@dixie-net.com(22740) |
Question 197786: This word problem is from a handout. I am a math tutor, but am so terrible at solving word problems. Can you give me any helpful advice or direction on how to get better at these???
Here is one from a student's handout sheet. I hope that I got it right, but not at all sure:
A PASSENGER PLANE FLEW TO MOSCON AND BACK. IT TOOK THREE HOURS LONGER TO GO THERE THAN IT DID TO COME BACK. THE AVERAGE SPEED ON THE TRIP THERE WAS 196 kn/h. THE AVERAGE SPEED ON THE WAY BACK WAS 280 km/h. HOW MANY HOURS DID THE TRIP THERE TAKE?
I solved it as follows:
196x = 280(x-3)
x = 10
trip to = 10 hours
trip back = 7 hours
total trip took 17 hours??????
Thank you in advance for your help.
Click here to see answer by nerdybill(7384)  |
Question 197791: This is another problem from a handout. Please let me know if I got it right???
A DIESEL TRAIN LEFT THE STATION TEN HOURS BEFORE A FREIGHT TRAIN. THE TRAINS TRAVELED IN OPPOSITE DIRECTIONS. THE FREIGHT TRAIN TRAVELED AT 20 mph FOR ONE HOUR. AFTER THIS TIME THE TRAINS WERE 680 MILES APART. FIND THE DIESEL TRAIN'S SPEED.
I got 22mph for the diesel.
20x + 20(x-10) = 680
Thank you in advance for your help.
Click here to see answer by edjones(8007)  |
Question 197791: This is another problem from a handout. Please let me know if I got it right???
A DIESEL TRAIN LEFT THE STATION TEN HOURS BEFORE A FREIGHT TRAIN. THE TRAINS TRAVELED IN OPPOSITE DIRECTIONS. THE FREIGHT TRAIN TRAVELED AT 20 mph FOR ONE HOUR. AFTER THIS TIME THE TRAINS WERE 680 MILES APART. FIND THE DIESEL TRAIN'S SPEED.
I got 22mph for the diesel.
20x + 20(x-10) = 680
Thank you in advance for your help.
Click here to see answer by ptaylor(2198)  |
Question 197838: Junior's boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed fo the current?
I am not even sure where to start here... I'm freaking out!
Click here to see answer by solver91311(24713) |
Question 197812: 109. Diving time. The time t (in seconds) that it takes for a cliff diver to reach the water is determined by the height h (in feet) from which he dives:
t=~((h)/(16))
a) Use the properties of radicals to simplify this formula.
b) Find the exact time (according to the formula) that it takes a diver to hit the water when diving from a height of 40 feet.
c) Use the graph to estimate the height if a diver takes 2.5 seconds to reach the water.
I need the following problem solved/using ex:109
110. Sky diving. The formula in Exercise 109 accounts for the effect of gravity only on a falling object. According to that formula, how long would it take a sky diver to reach the earth when jumping from 17,000 feet? (A skydiver can actually get about twice as much falling time by spreading out and using the air to slow the fall.)
Click here to see answer by ankor@dixie-net.com(22740) |
Question 197836: Filling a tank.
A water tank has an inlet pipe and a drain pipe. A full tank can be emptied in 30 minutes if the draing is opened and an empty tank can be filled in 45 minutes with the inlet pipe opened. If both pipes are accidentally opened when the tank is full, then how long will it take to empty the tank?
Click here to see answer by stanbon(75887) |
Question 197875: Leaving from her house, Mary leaves Pittsburgh in her car traveling towards Cleveland at 3PM. She travels at an average rate of 30 mi an hour. Mary's brother Jack leaves the house an hour later and follows the same route as Mary. He travels at an average rate of 60 mi. hr. How long will it take to catch up to Mary?
Click here to see answer by stanbon(75887) |
Question 197923: There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second? I need help setting up the equation...plez. thank you
Click here to see answer by nerdybill(7384) |
Question 197923: There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second? I need help setting up the equation...plez. thank you
Click here to see answer by josmiceli(19441) |
Question 198139: This is a problem from the Jubilee Academy's online homeschooling website, which I am enrolled in.
A freight train leaves a station traveling a constant speed of 30 miles per hour (mph). A passenger train leaves at the same time and travels in the same direction at a constant speed of 35 mph. In how many hours will the trains be 15 miles apart?
I would be able to do this problem easily if i knew how to set up the equation, which is for me the hardest part, but there were no similar solvers in the travel and distance section. Thank you.
Click here to see answer by RAY100(1637) |
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27136..27180, 27181..27225, 27226..27270, 27271..27315, 27316..27360, 27361..27405, 27406..27450, 27451..27495, 27496..27540, 27541..27585, 27586..27630, 27631..27675, 27676..27720, 27721..27765, 27766..27810, 27811..27855, 27856..27900, 27901..27945, 27946..27990, 27991..28035, 28036..28080, 28081..28125, 28126..28170, 28171..28215, 28216..28260, 28261..28305, 28306..28350, 28351..28395, 28396..28440, 28441..28485, 28486..28530, 28531..28575, 28576..28620, 28621..28665, 28666..28710, 28711..28755, 28756..28800, 28801..28845, 28846..28890, 28891..28935, 28936..28980, 28981..29025, 29026..29070, 29071..29115, 29116..29160, 29161..29205, 29206..29250, 29251..29295, 29296..29340, 29341..29385, 29386..29430, 29431..29475, 29476..29520, 29521..29565, 29566..29610, 29611..29655, 29656..29700, 29701..29745, 29746..29790, 29791..29835, 29836..29880, 29881..29925, 29926..29970, 29971..30015, 30016..30060, 30061..30105, 30106..30150, 30151..30195, 30196..30240, 30241..30285, 30286..30330, 30331..30375, 30376..30420, 30421..30465, 30466..30510, 30511..30555, 30556..30600, 30601..30645, 30646..30690, 30691..30735, 30736..30780, 30781..30825, 30826..30870, 30871..30915, 30916..30960, 30961..31005, 31006..31050, 31051..31095, 31096..31140, 31141..31185, 31186..31230, 31231..31275, 31276..31320, 31321..31365, 31366..31410, 31411..31455, 31456..31500, 31501..31545, 31546..31590, 31591..31635, 31636..31680, 31681..31725, 31726..31770, 31771..31815, 31816..31860, 31861..31905, 31906..31950, 31951..31995, 31996..32040, 32041..32085, 32086..32130, 32131..32175, 32176..32220, 32221..32265, 32266..32310, 32311..32355, 32356..32400, 32401..32445, 32446..32490, 32491..32535, 32536..32580, 32581..32625, 32626..32670, 32671..32715, 32716..32760, 32761..32805, 32806..32850, 32851..32895, 32896..32940, 32941..32985, 32986..33030, 33031..33075, 33076..33120, 33121..33165, 33166..33210, 33211..33255, 33256..33300, 33301..33345, 33346..33390, 33391..33435, 33436..33480, 33481..33525, 33526..33570, 33571..33615, 33616..33660, 33661..33705, 33706..33750, 33751..33795, 33796..33840, 33841..33885, 33886..33930, 33931..33975, 33976..34020, 34021..34065, 34066..34110, 34111..34155, 34156..34200, 34201..34245, 34246..34290, 34291..34335, 34336..34380, 34381..34425, 34426..34470, 34471..34515, 34516..34560, 34561..34605, 34606..34650, 34651..34695, 34696..34740, 34741..34785, 34786..34830, 34831..34875, 34876..34920, 34921..34965, 34966..35010, 35011..35055, 35056..35100, 35101..35145, 35146..35190, 35191..35235, 35236..35280, 35281..35325, 35326..35370, 35371..35415, 35416..35460, 35461..35505, 35506..35550, 35551..35595, 35596..35640, 35641..35685, 35686..35730, 35731..35775, 35776..35820, 35821..35865, 35866..35910, 35911..35955, 35956..36000, 36001..36045, 36046..36090, 36091..36135, 36136..36180, 36181..36225, 36226..36270, 36271..36315, 36316..36360, 36361..36405, 36406..36450, 36451..36495, 36496..36540, 36541..36585, 36586..36630, 36631..36675, 36676..36720, 36721..36765, 36766..36810, 36811..36855, 36856..36900, 36901..36945, 36946..36990, 36991..37035, 37036..37080, 37081..37125, 37126..37170, 37171..37215, 37216..37260, 37261..37305, 37306..37350, 37351..37395, 37396..37440, 37441..37485, 37486..37530, 37531..37575, 37576..37620
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