Tutors Answer Your Questions about Travel Word Problems (FREE)
Question 884036: Sam lives 45 miles due West of where he works. Everyday he drives on the highway at 65 mph. Jim works in the same building, and lives 30 miles due East, but is only able to drive 40 mph. If they do not stop at the building where they work and just kept on driving, after how much time would they pass each other on the road? Round to the nearest THOUSANDTH of an hour.
Click here to see answer by josgarithmetic(39613) |
Question 884129: Two trains leave the station at the same time, one heading west and the other east. The westbound train travels miles per hour faster than the eastbound train. If the two trains are miles apart after hours, what is the rate of the westbound train?
Click here to see answer by Alan3354(69443)  |
Question 884133: suppose you have entered a 62 mile biathlon that consist of a run and a bicycle race. during your run your average velocity is 8mph and during your bicycle race your average velocity is 20mph. you finished the race in 4 hrs. what is the distance of the run?
Click here to see answer by lwsshak3(11628) |
Question 884351: Two cyclists start on a circular track from a given point but in opposite directions with speeds of 7 m/sec and 8 m/sec respectively. If the circumference of the circle is 300 meters,after what time will they meet at the starting point ?
Click here to see answer by stanbon(75887) |
Question 884315: A car traveled 120 miles in the same amount of time that it took an airplane
to travel 1050 miles. The speed of the airplane was 310 miles per hour faster than the speed of the car. Find the speed of the airplane.
Click here to see answer by geetha_rama(94) |
Question 884254: Jane works due north of her home. Her husband Juan works due east. They leave for work at the same time. By the time Jane is 7 miles from home, the distance between then is only 1 mile more than Juans distance from home. How far from home is Juan?
Click here to see answer by lwsshak3(11628) |
Question 884384: A bus started from town A for town B, 160 km away. After traveling 20 km, it was detained for 20 minutes. In order to reach B on schedule, it traveled the rest of the way at the rate of 10 kph faster. Find the original speed.
Click here to see answer by geetha_rama(94) |
Question 884369: Pa got in his '27 ford and started driving west from Memphis at a constant speen of 40 mph. An hour later ma got in her '34 Buick and started driving west from Memphis at a constant speed. After driving 4 hours ma had passed pea and was 20 miles ahead of him. How fast was ma driving?
Click here to see answer by lwsshak3(11628) |
Question 884415: Pa got in his '27 ford and started driving west from Memphis at a constant speed of 40 mph. An hour later ma got in her '34 Buick and started driving west from Memphis at a constant speed. After driving 4 hours ma had passed pa and was 20 miles ahead of him. How fast was ma driving?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 884587: You are standing 1/3 of the length in on the bridge and can run with a speed of 20 Km/h
Here we can choose two scenarios:
1. You run 1/3 of the bridge's length in the direction of the train and is just fast enough to fling you off the bridge before being hit by the train.
2. You run 2/3 of the bridge's length away from the train, also here just in time to throw you off the bridge before the train hit you.
What is the speed of the train?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 884616: jJoe and Louise are making a drive from San Diego to Salt Lake City. After 4 hours of driving, they are 507 miles from Salt Lake City. Eight hours into their trip, they are only 267 miles away from their destination. Assume they averaged the same speed for the entire trip.
Question 1. In how many hours will they reach Salt Lake City from time they left San Diego?
2. How far from Salt Lake City will they be after 10 hours of driving?
3. When will they be 300 miles from Salt Lake City?
4. What is the distance from San Diego to Salt Lake City?
Please help me..
Click here to see answer by josgarithmetic(39613) |
Question 884189: Going Round-Trip with the World’s Fastest Land Animal
According to the Travel Almanac, the world’s fastest land animal is the cheetah. It can travel at up to 70 mph. Think of this scenario: A cheetah sitting under a tree sprints toward its prey at 70 mph. It runs back to its initial spot by the tree at a modest 40 mph. The cheetah has embarked on a round-trip. Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.
Can we say that this cheetah’s average rate was 55 mph?
That’s one of the things you’ll determine as you work to complete this task. Make a conjecture. What do you think the answer will be?
If the cheetah sprinted at maximum speed, how far would the cheetah have traveled?
a. Set up an equation to represent the distance the cheetah covered in terms of t minutes running at maximum speed. Remember, units of distance and time must agree. Use the conversion information from the warm-up to write a rate in miles per minute.
b. Let t = 10 and solve for the distance the cheetah covered in 10 minutes.
Step 2: Calculating distance using varied speeds
Suppose the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes.
a. How far would the cheetah have traveled in the first 8 minutes? Show how you arrived at your answer.
b. How far would the cheetah have traveled in the next 8 minutes? Show how you arrived at your answer.
c. How much farther did the cheetah travel in the first 8 minutes than in the second 8 minutes?
d. The cheetah traveled 1.75 times faster for the first 8 minutes than it did for the second 8 minutes. Was the distance traveled during the first 8 minutes 1.75 times greater than the distance traveled during the second 8 minutes? Show the calculation to justify your answer.
e. If the cheetah made a round-trip and took half the amount of time on the return trip as on the front end of the trip, what would be the relationship between the average rates on each leg of the trip? Using a complete sentence, explain how you arrived at this conclusion.
Step 3: Calculating time
Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to its resting place, the cheetah travels an average of 70 mph. If the cheetah traveled for 15 minutes, how many minutes did the return trip take to the nearest minute and second?
a. Set up the table as follows. Label the rows “To the River” and “From the River.” Label the columns “Distance,” “Rate,” and “Time (in Hours).” Let t represent the unknown quantity in the problem. Fill in the table.
b. From the table, set up an equation relating the distances.
c. Solve the problem. Write the answer in a complete sentence, stating it in terms of minutes and seconds.
Now it’s time to tackle the original question.
Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.
Can we say that this cheetah’s average rate was 55 mph?
a. The average rate for the trip is equal to the total distance traveled divided by the total time traveled. The following equations represent the distance traveled on each leg of the trip.
First leg of trip: 𝑑=𝑟1𝑡1
Second leg of trip: 𝑑=𝑟2𝑡2
Write an equation for the average rate for the trip. Remember, the cheetah runs from point A to point B and back to point A.
)
b. The following equation represents the average rate for the trip. Is this equation equivalent to the one you wrote above? Explain why or why not.
)
c. The following steps show how the equation for the average rate can be transformed so that it is written in terms of only the rates for each leg of the trip. Write an algebraic justification for each step. Think about the number operations and properties that you know.
(
)
(
)
(
d. Using the equation for average rate above, determine the cheetah’s average rate for the entire trip.
Click here to see answer by richwmiller(17219)  |
Question 884189: Going Round-Trip with the World’s Fastest Land Animal
According to the Travel Almanac, the world’s fastest land animal is the cheetah. It can travel at up to 70 mph. Think of this scenario: A cheetah sitting under a tree sprints toward its prey at 70 mph. It runs back to its initial spot by the tree at a modest 40 mph. The cheetah has embarked on a round-trip. Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.
Can we say that this cheetah’s average rate was 55 mph?
That’s one of the things you’ll determine as you work to complete this task. Make a conjecture. What do you think the answer will be?
If the cheetah sprinted at maximum speed, how far would the cheetah have traveled?
a. Set up an equation to represent the distance the cheetah covered in terms of t minutes running at maximum speed. Remember, units of distance and time must agree. Use the conversion information from the warm-up to write a rate in miles per minute.
b. Let t = 10 and solve for the distance the cheetah covered in 10 minutes.
Step 2: Calculating distance using varied speeds
Suppose the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes.
a. How far would the cheetah have traveled in the first 8 minutes? Show how you arrived at your answer.
b. How far would the cheetah have traveled in the next 8 minutes? Show how you arrived at your answer.
c. How much farther did the cheetah travel in the first 8 minutes than in the second 8 minutes?
d. The cheetah traveled 1.75 times faster for the first 8 minutes than it did for the second 8 minutes. Was the distance traveled during the first 8 minutes 1.75 times greater than the distance traveled during the second 8 minutes? Show the calculation to justify your answer.
e. If the cheetah made a round-trip and took half the amount of time on the return trip as on the front end of the trip, what would be the relationship between the average rates on each leg of the trip? Using a complete sentence, explain how you arrived at this conclusion.
Step 3: Calculating time
Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to its resting place, the cheetah travels an average of 70 mph. If the cheetah traveled for 15 minutes, how many minutes did the return trip take to the nearest minute and second?
a. Set up the table as follows. Label the rows “To the River” and “From the River.” Label the columns “Distance,” “Rate,” and “Time (in Hours).” Let t represent the unknown quantity in the problem. Fill in the table.
b. From the table, set up an equation relating the distances.
c. Solve the problem. Write the answer in a complete sentence, stating it in terms of minutes and seconds.
Now it’s time to tackle the original question.
Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.
Can we say that this cheetah’s average rate was 55 mph?
a. The average rate for the trip is equal to the total distance traveled divided by the total time traveled. The following equations represent the distance traveled on each leg of the trip.
First leg of trip: 𝑑=𝑟1𝑡1
Second leg of trip: 𝑑=𝑟2𝑡2
Write an equation for the average rate for the trip. Remember, the cheetah runs from point A to point B and back to point A.
)
b. The following equation represents the average rate for the trip. Is this equation equivalent to the one you wrote above? Explain why or why not.
)
c. The following steps show how the equation for the average rate can be transformed so that it is written in terms of only the rates for each leg of the trip. Write an algebraic justification for each step. Think about the number operations and properties that you know.
(
)
(
)
(
d. Using the equation for average rate above, determine the cheetah’s average rate for the entire trip.
Click here to see answer by Alan3354(69443)  |
Question 884681: You are travelling to the scene of an accident, and the traffic is terrible. Your average speed has slowed to 30 km/h. Assuming you still have another 10 km to travel, and your speed does not change, how long will it take
Click here to see answer by skartikey(21)  |
Question 884680: the post office building in manilais 21.8 meters away from the southern bank of the pasig river. from a window of the building 18.5 meters above the ground, a man finds that the angle of depression of the northern bank is 8 degrees and 12 minutes. what is the width of the river at this point?
Click here to see answer by lwsshak3(11628) |
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27136..27180, 27181..27225, 27226..27270, 27271..27315, 27316..27360, 27361..27405, 27406..27450, 27451..27495, 27496..27540, 27541..27585, 27586..27630, 27631..27675, 27676..27720, 27721..27765, 27766..27810, 27811..27855, 27856..27900, 27901..27945, 27946..27990, 27991..28035, 28036..28080, 28081..28125, 28126..28170, 28171..28215, 28216..28260, 28261..28305, 28306..28350, 28351..28395, 28396..28440, 28441..28485, 28486..28530, 28531..28575, 28576..28620, 28621..28665, 28666..28710, 28711..28755, 28756..28800, 28801..28845, 28846..28890, 28891..28935, 28936..28980, 28981..29025, 29026..29070, 29071..29115, 29116..29160, 29161..29205, 29206..29250, 29251..29295, 29296..29340, 29341..29385, 29386..29430, 29431..29475, 29476..29520, 29521..29565, 29566..29610, 29611..29655, 29656..29700, 29701..29745, 29746..29790, 29791..29835, 29836..29880, 29881..29925, 29926..29970, 29971..30015, 30016..30060, 30061..30105, 30106..30150, 30151..30195, 30196..30240, 30241..30285, 30286..30330, 30331..30375, 30376..30420, 30421..30465, 30466..30510, 30511..30555, 30556..30600, 30601..30645, 30646..30690, 30691..30735, 30736..30780, 30781..30825, 30826..30870, 30871..30915, 30916..30960, 30961..31005, 31006..31050, 31051..31095, 31096..31140, 31141..31185, 31186..31230, 31231..31275, 31276..31320, 31321..31365, 31366..31410, 31411..31455, 31456..31500, 31501..31545, 31546..31590, 31591..31635, 31636..31680, 31681..31725, 31726..31770, 31771..31815, 31816..31860, 31861..31905, 31906..31950, 31951..31995, 31996..32040, 32041..32085, 32086..32130, 32131..32175, 32176..32220, 32221..32265, 32266..32310, 32311..32355, 32356..32400, 32401..32445, 32446..32490, 32491..32535, 32536..32580, 32581..32625, 32626..32670, 32671..32715, 32716..32760, 32761..32805, 32806..32850, 32851..32895, 32896..32940, 32941..32985, 32986..33030, 33031..33075, 33076..33120, 33121..33165, 33166..33210, 33211..33255, 33256..33300, 33301..33345, 33346..33390, 33391..33435, 33436..33480, 33481..33525, 33526..33570, 33571..33615, 33616..33660, 33661..33705, 33706..33750, 33751..33795, 33796..33840, 33841..33885, 33886..33930, 33931..33975, 33976..34020, 34021..34065, 34066..34110, 34111..34155, 34156..34200, 34201..34245, 34246..34290, 34291..34335, 34336..34380, 34381..34425, 34426..34470, 34471..34515, 34516..34560, 34561..34605, 34606..34650, 34651..34695, 34696..34740, 34741..34785, 34786..34830, 34831..34875, 34876..34920, 34921..34965, 34966..35010, 35011..35055, 35056..35100, 35101..35145, 35146..35190, 35191..35235, 35236..35280, 35281..35325, 35326..35370, 35371..35415, 35416..35460, 35461..35505, 35506..35550, 35551..35595, 35596..35640, 35641..35685, 35686..35730, 35731..35775, 35776..35820, 35821..35865, 35866..35910, 35911..35955, 35956..36000, 36001..36045, 36046..36090, 36091..36135, 36136..36180, 36181..36225, 36226..36270, 36271..36315, 36316..36360, 36361..36405, 36406..36450, 36451..36495, 36496..36540, 36541..36585, 36586..36630, 36631..36675, 36676..36720, 36721..36765, 36766..36810, 36811..36855, 36856..36900, 36901..36945, 36946..36990, 36991..37035, 37036..37080, 37081..37125, 37126..37170, 37171..37215, 37216..37260, 37261..37305, 37306..37350, 37351..37395, 37396..37440, 37441..37485, 37486..37530, 37531..37575, 37576..37620
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