SOLUTION: As part of a conditioning program, a jogger ran 9 mi in the same amount of time as it took a cyclist to ride 27 mi. The rate of the cyclist was 18 mph faster than the rate of the j

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Question 976007: As part of a conditioning program, a jogger ran 9 mi in the same amount of time as it took a cyclist to ride 27 mi. The rate of the cyclist was 18 mph faster than the rate of the jogger. Find the rate of the jogger and the rate of the cyclist.
Answer by josgarithmetic(39799) About Me  (Show Source):
You can put this solution on YOUR website!
r, for jogger.
r+18, the rate of the bicyclist.

Look at the distances! bicyclist goes three times faster than the jogger.
r%2B18=3r, solve.


If that seems not so easy to decide and to form, then make a data table and use RT=D to analyze and find what and how to solve.



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r=9 miles per hour, the jogger.